If frac{5}{m}+frac{2}{n}=9 and frac{3}{m}+fra | vedclass

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(C) Let $x = \frac{1}{m}$ and $y = \frac{1}{n}$.Then the given equations become:$5x + 2y = 9$  --- $(1)$$3x + 4y = 11$ --- $(2)$Multiply equation $(1)

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$1$ and $\frac{1}{2}$

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(C) Let $x = \frac{1}{m}$ and $y = \frac{1}{n}$.Then the given equations become:$5x + 2y = 9$  --- $(1)$$3x + 4y = 11$ --- $(2)$Multiply equation $(1)$ by $2$ to eliminate $y$:$10x + 4y = 18$ --- $(3)$Subtract equation $(2)$ from equation $(3)$:$(10x - 3x) + (4y - 4y) = 18 - 11$$7x = 7 \implies x = 1$Substitute $x = 1$ into equation $(1)$:$5(1) + 2y = 9$$5 + 2y = 9 \implies 2y = 4 \implies y = 2$Since $x = \frac{1}{m} = 1$,we get $m = 1$.Since $y = \frac{1}{n} = 2$,we get $n = \frac{1}{2}$.Thus,the values are $m = 1$ and $n = \frac{1}{2}$.

If $\frac{5}{m}+\frac{2}{n}=9$ and $\frac{3}{m}+\frac{4}{n}=11$ and $mn \neq 0$,then the values of $m$ and $n$ are . . . . . . respectively.

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