If tan ^{-1} x = y,then . . . . . . . | vedclass

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(D) The function $y = 	an^{-1} x$ is the inverse of the tangent function restricted to the interval $(-\frac{\pi}{2}, \frac{\pi}{2})$.By definition,t

Vedclass · Accepted Answer

$\frac{-\pi}{2} < y < \frac{\pi}{2}$

Vedclass · Answer

(D) The function $y = 	an^{-1} x$ is the inverse of the tangent function restricted to the interval $(-\frac{\pi}{2}, \frac{\pi}{2})$.By definition,the range of the principal value branch of $y = 	an^{-1} x$ is the open interval $(-\frac{\pi}{2}, \frac{\pi}{2})$.Therefore,the correct condition is $\frac{-\pi}{2} Thus,the correct option is $D$.

If $\tan ^{-1} x = y$,then . . . . . . .

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