If $\cos ^{-1} x = y$,then . . . . . . .
- A$-\frac{\pi}{2} < y < \frac{\pi}{2}$
- B$-\frac{\pi}{2} \leq y \leq \frac{\pi}{2}$
- C$0 < y < \pi$
- D$0 \leq y \leq \pi$
Explore More
Similar Questions
The domain of the function $f(x) = \sqrt{\cos^{-1}\left(\frac{1-|x|}{2}\right)}$ is
DifficultWBJEE 2010
View SolutionThe domain of the function $f(x) = \sin^{-1}\left(\frac{|x|+5}{x^2+1}\right)$ is $(-\infty, -a] \cup [a, \infty)$. Then $a$ is equal to
DifficultJEE MAIN 2020
View SolutionDomain of $\sin^{-1}$ is . . . . . . .
Let $f:(-1, 1) \to B$ be a function defined by $f(x) = \tan^{-1}\left(\frac{2x}{1-x^2}\right)$. Then $f$ is both one-one and onto when $B$ is the interval:
The range of $\tan^{-1} x$ is
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo