यदि 2y,cos theta = xsin ,theta {rm{ and }}2xs | vedclass

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Question

(a) दिया है $2y\,\,\cos 	heta  = x\,\sin 	heta $&hellip;..$(i)$

एवं $2x\,\sec 	heta  - y\,\,{m{cosec}}\,	heta  = 3$&hellip;..$

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(a) दिया है $2y\,\,\cos 	heta  = x\,\sin 	heta $&hellip;..$(i)$

एवं $2x\,\sec 	heta  - y\,\,{m{cosec}}\,	heta  = 3$&hellip;..$(ii)$

$ \Rightarrow \,\,\frac{{2x}}{{\cos 	heta }} - \frac{y}{{\sin 	heta }} = 3$

$ \Rightarrow \,\,2x\,\sin 	heta  - y\,\cos 	heta  - 3\,\sin 	heta \cos 	heta  = 0$&hellip;..$(iii)$

$(i)$ व $(iii)$ को हल करने पर,

$y = \sin 	heta $ एवं $x = 2\,\,\cos 	heta $

अब, ${x^2} + 4{y^2} = 4\,\,{\cos ^2}	heta  + 4\,\,{\sin ^2}	heta $

$ = 4\,({\cos ^2}	heta  + {\sin ^2}	heta ) = 4$.

यदि $2y\,\cos \theta = x\sin \,\theta {\rm{ and }}2x\sec \theta - y\,{\rm{cosec}}\,\theta = 3,$ तो ${x^2} + 4{y^2} = $

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