If $M_{O}$ is the mass of an oxygen isotope ${ }_{8}^{17}O$, $M_{p}$ and $M_{n}$ are the masses of a proton and a neutron, respectively, the nuclear binding energy of the isotope is

  • A
    $(M_{O}-8 M_{p}) c^{2}$
  • B
    $(M_{O}-8 M_{p}-9 M_{n}) c^{2}$
  • C
    $M_{O} c^{2}$
  • D
    $(M_{O}-17 M_{n}) c^{2}$

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The curve of binding energy per nucleon as a function of atomic mass number has a sharp peak for the helium nucleus. This implies that helium

${ }_{92}^{238} A \rightarrow{ }_{90}^{234} B +{ }_2^4 D + Q$
In the given nuclear reaction,the approximate amount of energy released will be $.....\,MeV$.
[Given: mass of ${ }_{92}^{238} A = 238.05079 \, u$,mass of ${ }_{90}^{234} B = 234.04363 \, u$,mass of ${ }_2^4 D = 4.00260 \, u$,and $1 \, u = 931.5 \, MeV/c^2$]

In a nuclear reaction,which of the following is conserved?

If the binding energy of deuterium is $2.23 \, MeV$, then its mass defect is ........ $amu$.

Given below are two statements:
Statement $I$: For all elements,greater the mass of the nucleus,greater is the binding energy per nucleon.
Statement $II$: For all elements,nuclei with less binding energy per nucleon transform to nuclei with greater binding energy per nucleon.
In the light of the above statements,choose the correct answer from the options given below:

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