If A = [1, 2, 3],B = begin{bmatrix} 2 3 4 e | vedclass

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(B) Given matrices are $A_{1 	imes 3} = [1, 2, 3]$,$B_{3 	imes 1} = \begin{bmatrix} 2 \ 3 \ 4 \end{bmatrix}$,and $C_{2 	imes 2} = \begin{bmatrix}

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$BA$

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(B) Given matrices are $A_{1 	imes 3} = [1, 2, 3]$,$B_{3 	imes 1} = \begin{bmatrix} 2 \ 3 \ 4 \end{bmatrix}$,and $C_{2 	imes 2} = \begin{bmatrix} 1 & 5 \ 0 & 2 \end{bmatrix}$.For the product of two matrices $X$ and $Y$ to be defined,the number of columns in $X$ must be equal to the number of rows in $Y$.$1$. For $AC$: $A$ is $1 	imes 3$ and $C$ is $2 	imes 2$. Since $3 
eq 2$,$AC$ is not defined.$2$. For $BA$: $B$ is $3 	imes 1$ and $A$ is $1 	imes 3$. Since $1 = 1$,$BA$ is defined. $BA = \begin{bmatrix} 2 \ 3 \ 4 \end{bmatrix} [1, 2, 3] = \begin{bmatrix} 2 & 4 & 6 \ 3 & 6 & 9 \ 4 & 8 & 12 \end{bmatrix}_{3 	imes 3}$.$3$. For $(AB)C$: $AB$ is defined ($1 	imes 3$ and $3 	imes 1$ results in $1 	imes 1$). Let $P = AB = [2(1) + 3(2) + 4(3)] = [20]_{1 	imes 1}$. Now,$PC$ requires $P$ to have $2$ columns,but it has $1$. Thus,$(AB)C$ is not defined.$4$. For $(AC)B$: Since $AC$ is not defined,$(AC)B$ is not defined.Therefore,$BA$ is the defined product.

If $A = [1, 2, 3]$,$B = \begin{bmatrix} 2 \\ 3 \\ 4 \end{bmatrix}$ and $C = \begin{bmatrix} 1 & 5 \\ 0 & 2 \end{bmatrix}$,then which of the following is defined?

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