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(B) Given the determinant equation: $\left| \begin{array}{ccc} 3x - 8 & 3 & 3 \ 3 & 3x - 8 & 3 \ 3 & 3 & 3x - 8 \end{array} ight| = 0$ Applying th

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$2/3, 11/3$

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(B) Given the determinant equation: $\left| \begin{array}{ccc} 3x - 8 & 3 & 3 \ 3 & 3x - 8 & 3 \ 3 & 3 & 3x - 8 \end{array} ight| = 0$ Applying the column operation $C_1 	o C_1 + C_2 + C_3$,we get: $(3x - 2) \left| \begin{array}{ccc} 1 & 3 & 3 \ 1 & 3x - 8 & 3 \ 1 & 3 & 3x - 8 \end{array} ight| = 0$ Applying row operations $R_1 	o R_1 - R_2$ and $R_2 	o R_2 - R_3$,we get: $(3x - 2) \left| \begin{array}{ccc} 0 & -3x + 11 & 0 \ 0 & 3x - 11 & -3x + 11 \ 1 & 3 & 3x - 8 \end{array} ight| = 0$ Expanding along the first column: $(3x - 2) \cdot 1 \cdot [(-3x + 11)(-3x + 11) - 0] = 0$ $(3x - 2)(3x - 11)^2 = 0$ Setting each factor to zero: $3x - 2 = 0 \implies x = 2/3$ $(3x - 11)^2 = 0 \implies x = 11/3$ Thus,the values of $x$ are $2/3$ and $11/3$.

If $\left| \begin{array}{ccc} 3x - 8 & 3 & 3 \\ 3 & 3x - 8 & 3 \\ 3 & 3 & 3x - 8 \end{array} \right| = 0$,then the values of $x$ are

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