If $R$ is the circumradius of $\triangle ABC$,then the area of $\triangle ABC$ is equal to $\ldots$.

  • A
    $\frac{abc}{R}$
  • B
    $\frac{abc}{4R}$
  • C
    $\frac{abc}{3R}$
  • D
    $\frac{abc}{2R}$

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