If varphi is the angle between the lines a x^ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The angle $\varphi$ between the lines represented by $a x^{2}+2 h x y+b y^{2}=0$ is given by $	an \varphi = \left| \frac{2 \sqrt{h^{2}-a b}}{a+b}

Vedclass · Accepted Answer

$	heta$

Vedclass · Answer

(A) The angle $\varphi$ between the lines represented by $a x^{2}+2 h x y+b y^{2}=0$ is given by $	an \varphi = \left| \frac{2 \sqrt{h^{2}-a b}}{a+b} ight|$.For the equation $x^{2}+2 x y \sec 	heta+y^{2}=0$,we have $a=1$,$b=1$,and $h=\sec 	heta$.Substituting these values into the formula:$	an \varphi = \left| \frac{2 \sqrt{\sec^{2} 	heta - (1)(1)}}{1+1} ight|$$	an \varphi = \left| \frac{2 \sqrt{	an^{2} 	heta}}{2} ight|$$	an \varphi = 	an 	heta$.Therefore,the angle between the lines is $	heta$.

If $\varphi$ is the angle between the lines $a x^{2}+2 h x y+b y^{2}=0$,then the angle between the lines $x^{2}+2 x y \sec \theta+y^{2}=0$ is

Similar Questions

The lines $ax^2+2hxy+by^2=0$ are at right angles if

$ax^2-4xy-2y^2=0$ represents a pair of lines. If $\theta$ is the angle between these lines,$\cos \theta=\frac{1}{5}$ and the possible values of '$a$' are $a_1$ and $a_2$ $(a_1 < a_2)$,then $a_1+3a_2=$

The angle between the pair of straight lines $x^2 - y^2 - 2y - 1 = 0$ is....$^o$

If the lines represented by $(k^2+2) x^2+3 xy-6 y^2=0$ are perpendicular to each other,then the values of $k$ are

The angle $\theta$ between the pair of straight lines represented by the homogeneous equation $ax^2 + 2hxy + by^2 = 0$ is given by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module