If A = begin{bmatrix} 2 & 3 -4 & 1 end{bmatr | vedclass

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(D) Given $A = \begin{bmatrix} 2 & 3 \ -4 & 1 \end{bmatrix}$.First,calculate $A^2 = \begin{bmatrix} 2 & 3 \ -4 & 1 \end{bmatrix} \begin{bmatrix} 2 &

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$\begin{bmatrix} -21 & -63 \ 84 & 0 \end{bmatrix}$

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(D) Given $A = \begin{bmatrix} 2 & 3 \ -4 & 1 \end{bmatrix}$.First,calculate $A^2 = \begin{bmatrix} 2 & 3 \ -4 & 1 \end{bmatrix} \begin{bmatrix} 2 & 3 \ -4 & 1 \end{bmatrix} = \begin{bmatrix} 4-12 & 6+3 \ -8-4 & -12+1 \end{bmatrix} = \begin{bmatrix} -8 & 9 \ -12 & -11 \end{bmatrix}$.Now,calculate $3A^2 + 12A = 3 \begin{bmatrix} -8 & 9 \ -12 & -11 \end{bmatrix} + 12 \begin{bmatrix} 2 & 3 \ -4 & 1 \end{bmatrix}$.$= \begin{bmatrix} -24 & 27 \ -36 & -33 \end{bmatrix} + \begin{bmatrix} 24 & 36 \ -48 & 12 \end{bmatrix} = \begin{bmatrix} 0 & 63 \ -84 & -21 \end{bmatrix}$.Let $M = \begin{bmatrix} 0 & 63 \ -84 & -21 \end{bmatrix}$.The adjoint of a $2 	imes 2$ matrix $\begin{bmatrix} a & b \ c & d \end{bmatrix}$ is $\begin{bmatrix} d & -b \ -c & a \end{bmatrix}$.Therefore,$	ext{adj}(M) = \begin{bmatrix} -21 & -63 \ 84 & 0 \end{bmatrix}$.

If $A = \begin{bmatrix} 2 & 3 \\ -4 & 1 \end{bmatrix}$,then $\text{adj}(3A^2 + 12A)$ is equal to

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