If $\sin ^2 x + \cos ^2 y = 1$,then $\frac{dy}{dx} = $
- A$\frac{\sin ^2 x}{\sin ^2 y}$
- B$\frac{\sin ^2 y}{\sin ^2 x}$
- C$\frac{\sin 2x}{\sin 2y}$
- D$\frac{-\sin ^2 y}{\sin ^2 x}$
Explore More
Similar Questions
If $\ln (x + y) = 2xy$,then $y'(0) =$
MediumIIT 2004
View SolutionIf $y \sqrt{1-x^{2}}+x \sqrt{1-y^{2}}=1$,then $\frac{dy}{dx}=$
If $\log \sqrt{x^2+y^2}=\tan ^{-1}\left(\frac{x}{y}\right)$,then $\frac{d y}{d x}$ is equal to
If $y=x \tan y$,then $\frac{d y}{d x}=$
If $\log (x+y)=\sin (x+y)$,then $\frac{dy}{dx}$ is
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo