If $f(x) = \log(\sec^2 x)^{\cot^2 x}$ for $x \neq 0$ and $f(x) = K+1$ for $x=0$ is continuous at $x=0$,then the value of $K$ is

  • A
    $1$
  • B
    $e^{-1}$
  • C
    $0$
  • D
    $e$

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