If A, B, C are represented by 3 + 4i, 5 - 2i, | vedclass

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(A) The points are given by $A(3, 4), B(5, -2)$,and $C(-1, 16)$.To check if they are collinear,we calculate the area of the triangle formed by these p

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Collinear

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(A) The points are given by $A(3, 4), B(5, -2)$,and $C(-1, 16)$.To check if they are collinear,we calculate the area of the triangle formed by these points:$	ext{Area} = \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$$	ext{Area} = \frac{1}{2} |3(-2 - 16) + 5(16 - 4) + (-1)(4 - (-2))|$$	ext{Area} = \frac{1}{2} |3(-18) + 5(12) - 1(6)|$$	ext{Area} = \frac{1}{2} |-54 + 60 - 6| = \frac{1}{2} |0| = 0$.Since the area is $0$,the points $A, B, C$ are collinear.

If $A, B, C$ are represented by $3 + 4i, 5 - 2i, -1 + 16i$,then $A, B, C$ are

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