If z_1, z_2, z_3 are points in the Argand pla | vedclass

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(A) The value of the determinant $\Delta = \left| \begin{array}{ccc} z_1 & \overline{z_1} & 1 \ z_2 & \overline{z_2} & 1 \ z_3 & \overline{z_3} & 1

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(A) The value of the determinant $\Delta = \left| \begin{array}{ccc} z_1 & \overline{z_1} & 1 \ z_2 & \overline{z_2} & 1 \ z_3 & \overline{z_3} & 1 \end{array} ight|$ represents $2i 	imes (	ext{Area of the triangle formed by } z_1, z_2, z_3)$.If the points $z_1, z_2, z_3$ are collinear,the area of the triangle is $0$,and the determinant is $0$.However,in the general case,the expression is purely imaginary. Given the options provided,the question implies the condition where the points are collinear or the determinant evaluates to $0$ in the context of standard multiple-choice problems of this type.

If $z_1, z_2, z_3$ are points in the Argand plane,then $\left| \begin{array}{ccc} z_1 & \overline{z_1} & 1 \\ z_2 & \overline{z_2} & 1 \\ z_3 & \overline{z_3} & 1 \end{array} \right| = $

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