If z is a complex number,then (overline {{z^{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) We know that for any complex number $z$,the conjugate of the inverse is the inverse of the conjugate,i.e.,$\overline{z^{-1}} = (\overline{z})^{-1}

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(A) We know that for any complex number $z$,the conjugate of the inverse is the inverse of the conjugate,i.e.,$\overline{z^{-1}} = (\overline{z})^{-1}$.Therefore,$(\overline{z^{-1}})(\overline{z}) = (\overline{z})^{-1}(\overline{z})$.Since $(\overline{z})^{-1} = \frac{1}{\overline{z}}$,we have $\frac{1}{\overline{z}} 	imes \overline{z} = 1$,provided $z 
eq 0$.

If $z$ is a complex number,then $(\overline {{z^{ - 1}}} )(\overline z ) = $

Similar Questions

If $a = \cos \theta + i \sin \theta$,then $\frac{1 + a}{1 - a} = $

The modulus of the conjugate of $z = \frac{-2+i}{(1-2i)^2}$ is

If $(3+4i)^{2025} = 5^{2023}(x+iy)$,then $\sqrt{x^2+y^2} = $

Find the multiplicative inverse of $2-3i$.

If $Z = \alpha + i \beta$ satisfies the equation $|Z| - Z = 1 + 2i$ and $|Z| = \sqrt{\alpha^2 + \beta^2}$,then $Z \bar{Z} = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module