If n is a positive integer,then which of the | vedclass

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(B) We know that $i^2 = -1$,which implies $i^4 = (i^2)^2 = (-1)^2 = 1$. For any positive integer $n$,$i^{4n} = (i^4)^n = 1^n = 1$. Now,let us evaluate

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$i^{4n - 1} = i$

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(B) We know that $i^2 = -1$,which implies $i^4 = (i^2)^2 = (-1)^2 = 1$. For any positive integer $n$,$i^{4n} = (i^4)^n = 1^n = 1$. Now,let us evaluate the options: $A) i^{4n} = (i^4)^n = 1^n = 1$ (True). $B) i^{4n - 1} = i^{4n} 	imes i^{-1} = 1 	imes \frac{1}{i} = \frac{1}{i} 	imes \frac{i}{i} = \frac{i}{i^2} = \frac{i}{-1} = -i$ (False). $C) i^{4n + 1} = i^{4n} 	imes i^1 = 1 	imes i = i$ (True). $D) i^{-4n} = \frac{1}{i^{4n}} = \frac{1}{1} = 1$ (True). Thus,the relation $i^{4n - 1} = i$ is false.

If $n$ is a positive integer,then which of the following relations is false?

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