If $A(3, 1, -1)$,$B\left(\frac{5}{3}, \frac{7}{3}, \frac{1}{3}\right)$,$C(2, 2, 1)$ and $D\left(\frac{10}{3}, \frac{2}{3}, \frac{-1}{3}\right)$ are the vertices of a quadrilateral $ABCD$,then its area is

  • A
    $\frac{4 \sqrt{2}}{3}$
  • B
    $\frac{5 \sqrt{2}}{3}$
  • C
    $2 \sqrt{2}$
  • D
    $\frac{2 \sqrt{2}}{3}$

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