If $A =$ [$x:x$ is a multiple of $3$] and $B =$ [$x:x$ is a multiple of $5$], then $A -B$ is ($\bar A$ means complement of $A$)

  • A

    $\bar A \cap B$

  • B

    $A \cap \bar B$

  • C

    $\bar A \cap \bar B$

  • D

    $\overline {A \cap B} $

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