If $A =$ [$x:x$ is a multiple of $3$] and $B =$ [$x:x$ is a multiple of $5$], then $A -B$ is ($\bar A$ means complement of $A$)
If $A =$ [$x:x$ is a multiple of $3$] and $B =$ [$x:x$ is a multiple of $5$], then $A -B$ is ($\bar A$ means complement of $A$)
- A
$\bar A \cap B$
- B
$A \cap \bar B$
- C
$\bar A \cap \bar B$
- D
$\overline {A \cap B} $
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