If $A, B$ and $C$ are any three sets, then $A - (B \cap C)$ is equal to

Sets $A$ and $B$ have $3$ and $6$ elements respectively. What can be the minimum number of elements in $A \cup B$

Let $P=\{\theta: \sin \theta-\cos \theta=\sqrt{2} \cos \theta\}$ and $Q=\{\theta: \sin \theta+\cos \theta=\sqrt{2} \sin \theta\}$ be two sets. Then

If $A, B$ and $C$ are three sets such that  $A \cap B = A \cap C$ and $A \cup B = A \cup C$ then

Find the union of each of the following pairs of sets :

$A=\{1,2,3\}, B=\varnothing$ 

State whether each of the following statement is true or false. Justify you answer.

$\{2,6,10,14\}$ and $\{3,7,11,15\}$ are disjoint sets.