If vec{E} and vec{K} represent the electric f | vedclass

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Question

(A) For an electromagnetic wave,the relationship between the electric field $\vec{E}$,magnetic field $\vec{B}$,and the propagation vector $\vec{K}$ is

Vedclass · Accepted Answer

$\frac{1}{\omega}(\vec{K} 	imes \vec{E})$

Vedclass · Answer

(A) For an electromagnetic wave,the relationship between the electric field $\vec{E}$,magnetic field $\vec{B}$,and the propagation vector $\vec{K}$ is given by $\vec{B} = \frac{1}{\omega} (\vec{K} 	imes \vec{E})$.In an electromagnetic wave,the vectors $\vec{E}$,$\vec{B}$,and $\vec{K}$ form a right-handed system.The magnitude of the magnetic field is related to the electric field by $B = \frac{E}{c}$.Since the speed of light $c = \frac{\omega}{K}$,we have $B = \frac{E}{\omega/K} = \frac{K}{\omega} E$.Combining the direction and magnitude,we get $\vec{B} = \frac{1}{\omega} (\vec{K} 	imes \vec{E})$.

If $\vec{E}$ and $\vec{K}$ represent the electric field and propagation vectors of electromagnetic $(EM)$ waves in a vacuum,respectively,then the magnetic field vector $\vec{B}$ is given by: (where $\omega$ is the angular frequency).

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