If 5 theta is the measure of an acute angle a | vedclass

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(C) Given equation: $\cos 	heta = \sin 5 	heta$We know that $\sin(90^{\circ} - A) = \cos A$,so $\sin 5 	heta = \cos(90^{\circ} - 5 	heta)$.Substit

Vedclass · Accepted Answer

$15$

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(C) Given equation: $\cos 	heta = \sin 5 	heta$We know that $\sin(90^{\circ} - A) = \cos A$,so $\sin 5 	heta = \cos(90^{\circ} - 5 	heta)$.Substituting this into the equation: $\cos 	heta = \cos(90^{\circ} - 5 	heta)$.Since the cosine function is one-to-one for acute angles,we can equate the arguments:$	heta = 90^{\circ} - 5 	heta$$	heta + 5 	heta = 90^{\circ}$$6 	heta = 90^{\circ}$$	heta = \frac{90^{\circ}}{6} = 15^{\circ}$.

If $5 \theta$ is the measure of an acute angle and $\cos \theta = \sin 5 \theta$,then the value of $\theta$ is $\ldots \ldots \ldots \ldots$ (in $^{\circ}$)

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