$\frac{1}{\sin ^{2} \theta}-1 = \ldots \ldots \ldots$
- A$\cos ^{2} \theta$
- B$\cot ^{2} \theta$
- C$\tan ^{2} \theta$
- D$\sec ^{2} \theta$
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Similar Questions
State whether the following is 'True' or 'False' and justify your answer:
If $\cos A + \cos^2 A = 1$,then $\sin^2 A + \sin^4 A = 1$.
If $\cos A + \cos^2 A = 1$,then $\sin^2 A + \sin^4 A = 1$.
Medium
View SolutionIf $\tan A = \cot B$,then $A + B = \ldots$
Easy
View SolutionIf $\sin ^{2} 35^{\circ} + \cos ^{2} \theta = 1$,then $\theta = \ldots \ldots \ldots \ldots$ (in $^{\circ}$)
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View SolutionIf $\sin \theta + \cos \theta = p$ and $\sec \theta + \operatorname{cosec} \theta = q,$ then prove that $q(p^2 - 1) = 2p$.
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View SolutionProve that $\sqrt{\sec ^{2} \theta+\operatorname{cosec}^{2} \theta}=\tan \theta+\cot \theta$
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