If 2x + y = 23 and 4x - y = 19,find the value | vedclass

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(A) Given equations are:$2x + y = 23$  $(i)$$4x - y = 19$  $(ii)$Adding equation $(i)$ and $(ii)$:$(2x + y) + (4x - y) = 23 + 19$$6x = 42$$x = 7$Subst

Vedclass · Accepted Answer

$31, -\frac{5}{7}$

Vedclass · Answer

(A) Given equations are:$2x + y = 23$  $(i)$$4x - y = 19$  $(ii)$Adding equation $(i)$ and $(ii)$:$(2x + y) + (4x - y) = 23 + 19$$6x = 42$$x = 7$Substituting $x = 7$ in equation $(i)$:$2(7) + y = 23$$14 + y = 23$$y = 23 - 14 = 9$Now,calculating the required values:$5y - 2x = 5(9) - 2(7) = 45 - 14 = 31$$\frac{y}{x} - 2 = \frac{9}{7} - 2 = \frac{9 - 14}{7} = -\frac{5}{7}$Thus,the values are $31$ and $-\frac{5}{7}$.

If $2x + y = 23$ and $4x - y = 19$,find the values of $5y - 2x$ and $\frac{y}{x} - 2$.

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