If $\tan A = \frac{1 - \cos B}{\sin B}$,find $\tan 2A$ in terms of $\tan B$ and show that:
- A$\tan 2A = \tan B$
- B$\tan 2A = \tan^2 B$
- C$\tan 2A = \tan^2 B + 2\tan B$
- DNone of the above
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