If sin A = sin B and cos A = cos B, then | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given that $\sin A = \sin B$ and $\cos A = \cos B$. Squaring both equations and adding them: $\sin^2 A + \cos^2 A = \sin^2 B + \cos^2 B$ $1 = 1$ (

Vedclass · Accepted Answer

$\sin \frac{A - B}{2} = 0$

Vedclass · Answer

(A) Given that $\sin A = \sin B$ and $\cos A = \cos B$. Squaring both equations and adding them: $\sin^2 A + \cos^2 A = \sin^2 B + \cos^2 B$ $1 = 1$ (This is always true). Alternatively,consider $\cos A = \cos B$ and $\sin A = \sin B$. Subtracting the equations: $\cos A - \cos B = 0$ and $\sin A - \sin B = 0$. Using sum-to-product formulas: $-2 \sin \frac{A+B}{2} \sin \frac{A-B}{2} = 0$ $2 \cos \frac{A+B}{2} \sin \frac{A-B}{2} = 0$ For both to be zero,$\sin \frac{A-B}{2}$ must be $0$.

If $\sin A = \sin B$ and $\cos A = \cos B,$ then

Similar Questions

If $A + C = B,$ then $\tan A \tan B \tan C = $

If $\csc \theta = \frac{p + q}{p - q}$,then $\cot \left( \frac{\pi}{4} + \frac{\theta}{2} \right) = $

If $f(x) = \cos^2 x + \sec^2 x$,then its value is always:

The value of $\csc \frac{\pi}{18} - \sqrt{3} \sec \frac{\pi}{18}$ is a

Let ${f_k}(x) = \frac{1}{k}(\sin^k x + \cos^k x)$ for $k = 1, 2, 3, ...$. Then for all $x \in R$,the value of $f_4(x) - f_6(x)$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module