If A and B are two sets,then A cap (A cup B)' | vedclass

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(C) Using De Morgan's Law,we know that $(A \cup B)' = A' \cap B'$.Substituting this into the expression,we get $A \cap (A' \cap B')$.By the associativ

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$\phi$

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(C) Using De Morgan's Law,we know that $(A \cup B)' = A' \cap B'$.Substituting this into the expression,we get $A \cap (A' \cap B')$.By the associative law of sets,this can be rewritten as $(A \cap A') \cap B'$.Since $A \cap A' = \phi$ (the empty set),the expression becomes $\phi \cap B'$.Any set intersected with the empty set results in the empty set,so $\phi \cap B' = \phi$.

If $A$ and $B$ are two sets,then $A \cap (A \cup B)'$ is equal to

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