If 4,P(A) = 6,P(B) = 10,P(A cap B) = 1, then | vedclass

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(A) Given that $4\,P(A) = 1 \implies P(A) = \frac{1}{4}$.Given that $10\,P(A \cap B) = 1 \implies P(A \cap B) = \frac{1}{10}$.The conditional probabil

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$\frac{2}{5}$

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(A) Given that $4\,P(A) = 1 \implies P(A) = \frac{1}{4}$.Given that $10\,P(A \cap B) = 1 \implies P(A \cap B) = \frac{1}{10}$.The conditional probability is defined as $P\left( \frac{B}{A} ight) = \frac{P(A \cap B)}{P(A)}$.Substituting the values,we get $P\left( \frac{B}{A} ight) = \frac{1/10}{1/4} = \frac{1}{10} 	imes \frac{4}{1} = \frac{4}{10} = \frac{2}{5}$.

If $4\,P(A) = 6\,P(B) = 10\,P(A \cap B) = 1,$ then $P\left( \frac{B}{A} \right) = $

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