If a+b+c=0, then the value of frac{a^{2}+b^{2 | vedclass

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(C) Given that $a+b+c=0.$$\Rightarrow b+c=-a$Squaring both sides:$\Rightarrow (b+c)^{2}=(-a)^{2}$$\Rightarrow b^{2}+c^{2}+2bc=a^{2}$Now,add $a^{2}$ to

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$2$

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(C) Given that $a+b+c=0.$$\Rightarrow b+c=-a$Squaring both sides:$\Rightarrow (b+c)^{2}=(-a)^{2}$$\Rightarrow b^{2}+c^{2}+2bc=a^{2}$Now,add $a^{2}$ to both sides to match the numerator:$\Rightarrow a^{2}+b^{2}+c^{2}+2bc=2a^{2}$$\Rightarrow a^{2}+b^{2}+c^{2}=2a^{2}-2bc$$\Rightarrow a^{2}+b^{2}+c^{2}=2(a^{2}-bc)$Dividing both sides by $(a^{2}-bc)$:$\Rightarrow \frac{a^{2}+b^{2}+c^{2}}{a^{2}-bc}=2$

If $a+b+c=0,$ then the value of $\frac{a^{2}+b^{2}+c^{2}}{a^{2}-b c}$ is

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