What fraction must be subtracted from the sum | vedclass

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Question

(D) Let the fraction to be subtracted be $x$.According to the problem,the average of the three fractions is $\frac{1}{12}$.The three fractions are $\f

Vedclass · Accepted Answer

$\frac{1}{6}$

Vedclass · Answer

(D) Let the fraction to be subtracted be $x$.According to the problem,the average of the three fractions is $\frac{1}{12}$.The three fractions are $\frac{1}{4}$,$\frac{1}{6}$,and $-x$.The sum of these three fractions is $\frac{1}{4} + \frac{1}{6} - x$.The average is given by $\frac{	ext{Sum}}{3} = \frac{1}{12}$.Therefore,$\frac{\frac{1}{4} + \frac{1}{6} - x}{3} = \frac{1}{12}$.Multiplying both sides by $3$,we get $\frac{1}{4} + \frac{1}{6} - x = \frac{3}{12} = \frac{1}{4}$.Subtracting $\frac{1}{4}$ from both sides,we get $\frac{1}{6} - x = 0$.Thus,$x = \frac{1}{6}$.

What fraction must be subtracted from the sum of $\frac{1}{4}$ and $\frac{1}{6}$ to have an average of $\frac{1}{12}$ of all the three fractions?

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