If frac{x}{y} = frac{4}{5},then the value of | vedclass

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(B) Given $\frac{x}{y} = \frac{4}{5}$.To evaluate the expression $\frac{4}{7} + \frac{2y - x}{2y + x}$,divide the numerator and denominator of the sec

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(B) Given $\frac{x}{y} = \frac{4}{5}$.To evaluate the expression $\frac{4}{7} + \frac{2y - x}{2y + x}$,divide the numerator and denominator of the second term by $y$:$\frac{2y - x}{2y + x} = \frac{2 - (x/y)}{2 + (x/y)}$.Substitute $\frac{x}{y} = \frac{4}{5}$ into the expression:$= \frac{2 - (4/5)}{2 + (4/5)} = \frac{(10/5 - 4/5)}{(10/5 + 4/5)} = \frac{6/5}{14/5} = \frac{6}{14} = \frac{3}{7}$.Now,add this to the first term:$\frac{4}{7} + \frac{3}{7} = \frac{7}{7} = 1$.

If $\frac{x}{y} = \frac{4}{5}$,then the value of $\left(\frac{4}{7} + \frac{2y - x}{2y + x}\right)$ is

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