If $\frac{x^{2}-1}{x^{2}+1} \geq 0,$ then $x \in$

  • A
    $x \in(-\infty, -1] \cup [1, \infty)$
  • B
    $x \in [-1, 1]$
  • C
    $x \in \{-1, 1\}$
  • D
    $x \in (-\infty, -1) \cup (1, \infty)$

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