If $\alpha $ and $\beta $ are the eccentric angles of the extremities of a focal chord of an ellipse, then the eccentricity of the ellipse is

  • A

    $\frac{{\cos \,\alpha \, + \,\cos \,\beta }}{{\cos \,\left( {\alpha \, - \,\beta } \right)}}$

  • B

    $\frac{{\sin \,\alpha \, - \,\sin \,\beta }}{{\sin \,\left( {\alpha \, - \,\beta } \right)}}$

  • C

    $\frac{{\cos \,\alpha \, - \,\cos \,\beta }}{{\cos \,\left( {\alpha \, - \,\beta } \right)}}$

  • D

    $\frac{{\sin \,\alpha \, + \,\sin \,\beta }}{{\sin \,\left( {\alpha \, + \,\beta } \right)}}$

Similar Questions

Let a line $L$ pass through the point of intersection of the lines $b x+10 y-8=0$ and $2 x-3 y=0$, $b \in R -\left\{\frac{4}{3}\right\}$. If the line $L$ also passes through the point $(1,1)$ and touches the circle $17\left( x ^{2}+ y ^{2}\right)=16$, then the eccentricity of the ellipse $\frac{x^{2}}{5}+\frac{y^{2}}{b^{2}}=1$ is.

  • [JEE MAIN 2022]

The equations of the directrices of the ellipse $16{x^2} + 25{y^2} = 400$ are

In an ellipse, the distance between its foci is $6$ and minor axis is $8$. Then its eccentricity is

  • [AIEEE 2006]

Product of slopes of common tangents to the ellipse $\frac{x^2}{32} + \frac{y^2}{8} = 1$ and parabola $y^2 = 8x$ is -

The equation of the tangent to the ellipse ${x^2} + 16{y^2} = 16$ making an angle of ${60^o}$ with $x$ - axis is