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(D) The reaction of an alkyne with $Pd/BaSO_4$ (Lindlar's catalyst) produces a $cis$-alkene $(A)$.
The reaction of an alkyne with $Na/Liq. NH_3$

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Melting point $(A) >$ melting point $(B)$

Vedclass · Answer

(D) The reaction of an alkyne with $Pd/BaSO_4$ (Lindlar's catalyst) produces a $cis$-alkene $(A)$.
The reaction of an alkyne with $Na/Liq. NH_3$ (Birch reduction) produces a $trans$-alkene $(B)$.
$1$. Dipole moment: $cis$-alkenes $(A)$ have a non-zero dipole moment,while $trans$-alkenes $(B)$ have a dipole moment of nearly zero. Thus,$\vec{\mu}(A) > \vec{\mu}(B)$ is correct.
$2$. Boiling point: $cis$-alkenes $(A)$ are more polar than $trans$-alkenes $(B)$,so $A$ has a higher boiling point. Thus,boiling point $(A) >$ boiling point $(B)$ is correct.
$3$. Stability: $trans$-alkenes $(B)$ are more stable than $cis$-alkenes $(A)$ due to less steric hindrance. Thus,stability $(A) <$ stability $(B)$ is correct.
$4$. Melting point: $trans$-alkenes $(B)$ have a more symmetrical structure,allowing for better packing in the crystal lattice compared to $cis$-alkenes $(A)$. Therefore,the melting point of $B$ is higher than $A$. The statement melting point $(A) >$ melting point $(B)$ is incorrect.

Identify the wrong statement for the following reactions:
$R-C\equiv C-R \xrightarrow{Pd/BaSO_4} A$
$R-C\equiv C-R \xrightarrow{Na/Liq. NH_3} B$

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Identify the wrong statement for the following reactions: $R-C\equiv C-R \xrightarrow{Pd/BaSO_4} A$ $R-C\equiv C-R \xrightarrow{Na/Liq. NH_3} B$