Identify the major product formed from the se | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction sequence is as follows:$1$. Aniline $(C_6H_5NH_2)$ reacts with $NaNO_2/HCl$ at $273-278 \ K$ to form benzenediazonium chloride $(C_6H

Vedclass · Accepted Answer

Biphenyl

Vedclass · Answer

(B) The reaction sequence is as follows:$1$. Aniline $(C_6H_5NH_2)$ reacts with $NaNO_2/HCl$ at $273-278 \ K$ to form benzenediazonium chloride $(C_6H_5N_2^+Cl^-)$.$2$. Benzenediazonium chloride reacts with $Cu_2Cl_2$ (Sandmeyer reaction) to form chlorobenzene $(C_6H_5Cl)$.$3$. Chlorobenzene reacts with $Na$ in the presence of dry ether (Wurtz-Fittig reaction) to form biphenyl $(C_6H_5-C_6H_5)$.

Identify the major product formed from the sequence of reactions given below:
$C_6H_5NH_2$ $\xrightarrow[(ii) Cu_2Cl_2]{(i) NaNO_2/HCl, 273 K}$ $\xrightarrow{(iii) Na/dry ether} \text{Product}$

Similar Questions

The major product for the following reaction is:

The product $(X)$ is:

Select the correct statement:

Provide the chemical reactions for the following conversions:
$1$. $2$-bromopropane and $1$-bromopropane from propene.
$2$. $2$-bromopropane from $1$-bromopropane.

What is the product of the following reaction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Identify the major product formed from the sequence of reactions given below:$C_6H_5NH_2$ $\xrightarrow[(ii) Cu_2Cl_2]{(i) NaNO_2/HCl, 273 K}$ $\xrightarrow{(iii) Na/dry ether} \text{Product}$