Identify the logic gate represented by the gi | vedclass

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(A) The first gate is a $NAND$ gate with inputs $A$ and $B$. Its output is $\overline{A \cdot B}$.This output is fed into a $NAND$ gate whose two inpu

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$AND\, (A = 1, B = 1, Y = 1)$

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(A) The first gate is a $NAND$ gate with inputs $A$ and $B$. Its output is $\overline{A \cdot B}$.This output is fed into a $NAND$ gate whose two inputs are shorted together,which acts as a $NOT$ gate.Let the output of the first $NAND$ gate be $X = \overline{A \cdot B}$.The final output $Y$ is the inversion of $X$,so $Y = \overline{X} = \overline{(\overline{A \cdot B})} = A \cdot B$.Since the final output $Y = A \cdot B$,the circuit functions as an $AND$ gate.For $A = 1$ and $B = 1$,$Y = 1 \cdot 1 = 1$. Thus,option $A$ is correct.

Identify the logic gate represented by the given circuit and match the values of $A, B, Y$ in the bracket to verify.

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