Consider the circuit given below. Choose the | vedclass

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(D) The given circuit consists of a $NAND$ gate followed by a $NOT$ gate (since the second gate is an $OR$ gate with both inputs tied together,it acts

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(D) The given circuit consists of a $NAND$ gate followed by a $NOT$ gate (since the second gate is an $OR$ gate with both inputs tied together,it acts as a $NOT$ gate). Thus,the circuit is equivalent to a $NAND$ gate followed by a $NOT$ gate,which is an $AND$ gate. The output $Y$ is given by $Y = A \cdot B$. Truth table for the $AND$ gate:| $A$ | $B$ | $Y = A \cdot B$ ||---|---|---|| $0$ | $0$ | $0$ || $0$ | $1$ | $0$ || $1$ | $0$ | $0$ || $1$ | $1$ | $1$ |Based on the logic $Y = A \cdot B$,the output $Y$ is high $(1)$ only when both inputs $A$ and $B$ are high $(1)$. Otherwise,the output is low $(0)$.

Consider the circuit given below. Choose the sketch depicting the output $Y$ of this circuit having inputs $A$ and $B$ as given below.

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