Identify the compound which gives CO_2 more r | vedclass

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(C) The thermal stability of carbonates and bicarbonates determines how easily they release $CO_2$ upon heating. $NaHCO_3$ (sodium bicarbonate) decomp

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$NaHCO_3$

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(C) The thermal stability of carbonates and bicarbonates determines how easily they release $CO_2$ upon heating. $NaHCO_3$ (sodium bicarbonate) decomposes at a much lower temperature compared to the others: $2NaHCO_3 \rightarrow Na_2CO_3 + H_2O + CO_2$. $CaCO_3$ and $Li_2CO_3$ require significantly higher temperatures for decomposition,while $Na_2CO_3$ is thermally very stable and does not decompose easily.

Identify the compound which gives $CO_2$ more readily on heating.

Similar Questions

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