Potassium carbonate $(K_2CO_3)$ cannot be prepared by the Solvay process. Why?
(N/A) The Solvay process involves the reaction of $NH_3$,$CO_2$,and $NaCl$ to form $NaHCO_3$,which precipitates out because it is sparingly soluble in water.
In the case of potassium,$KHCO_3$ (potassium bicarbonate) is fairly soluble in water.
Therefore,it does not precipitate out of the solution,making it impossible to isolate the intermediate product required to produce $K_2CO_3$ via this method.
In the case of potassium,$KHCO_3$ (potassium bicarbonate) is fairly soluble in water.
Therefore,it does not precipitate out of the solution,making it impossible to isolate the intermediate product required to produce $K_2CO_3$ via this method.
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