(D) Step $1$: $1,2-\text{Dibromoethane}$ $(BrCH_2-CH_2Br)$ reacts with alcoholic $KOH$ (dehydrohalogenation) to form $A$,which is $Bromoethene$ $(CH_2

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(D) Step $1$: $1,2-\text{Dibromoethane}$ $(BrCH_2-CH_2Br)$ reacts with alcoholic $KOH$ (dehydrohalogenation) to form $A$,which is $Bromoethene$ $(CH_2=CHBr)$.Step $2$: $Bromoethene$ $(CH_2=CHBr)$ reacts with $NaNH_2$ (sodamide),a strong base,to undergo further dehydrohalogenation to form $B$,which is $Ethyne$ $(HC \equiv CH)$.