Identify A and B in the given reaction sequen | vedclass

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(C) The starting material is an $\alpha,\beta$-unsaturated ester (cyclohexylidene ethyl acetate). Step $1$: The reduction of an ester to a primary alc

Vedclass · Accepted Answer

$A = LiAlH_4, B = 	ext{Cyclohexylidene acetaldehyde}$

Vedclass · Answer

(C) The starting material is an $\alpha,\beta$-unsaturated ester (cyclohexylidene ethyl acetate). Step $1$: The reduction of an ester to a primary alcohol requires a strong reducing agent like $LiAlH_4$. $NaBH_4$ is generally not strong enough to reduce esters to alcohols. Therefore,$A = LiAlH_4$. Step $2$: The product formed is an allylic alcohol (cyclohexylidene ethanol). $MnO_2$ is a selective oxidizing agent that specifically oxidizes allylic and benzylic alcohols to their corresponding aldehydes or ketones without affecting other functional groups like the double bond. Thus,the oxidation of the primary allylic alcohol yields the corresponding aldehyde,cyclohexylidene acetaldehyde. Therefore,$A = LiAlH_4$ and $B = 	ext{Cyclohexylidene acetaldehyde}$.

Column-$I$ (Reactions)	Column-$II$ (Reagents)
$(i)$. Benzophenone $\rightarrow$ Diphenylmethane	$(a)$. $LiAlH_4$
$(ii)$. Benzaldehyde $\rightarrow$ $1-$Phenylethanol	$(b)$. $DIBAL-H$
$(iii)$. Cyclohexanone $\rightarrow$ Cyclohexanol	$(c)$. $Zn(Hg) / \text{Conc. } HCl$
$(iv)$. Phenyl benzoate $\rightarrow$ Benzaldehyde	$(d)$. $CH_3MgBr, H_2O$

Identify $A$ and $B$ in the given reaction sequence:
Cyclohexylidene ethyl acetate $\xrightarrow{A}$ Cyclohexylidene ethanol $\xrightarrow{MnO_2} B$

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Identify $A$ and $B$ in the given reaction sequence:Cyclohexylidene ethyl acetate $\xrightarrow{A}$ Cyclohexylidene ethanol $\xrightarrow{MnO_2} B$