Match the reactions given in column-I with th | vedclass

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(B) The correct matches are as follows:$(i)$. Benzophenone $ightarrow$ Diphenylmethane: This is a Clemmensen reduction,which uses $Zn(Hg) / 	ext{Co

Vedclass · Accepted Answer

$i-c, ii-d, iii-a, iv-b$

Vedclass · Answer

(B) The correct matches are as follows:$(i)$. Benzophenone $ightarrow$ Diphenylmethane: This is a Clemmensen reduction,which uses $Zn(Hg) / 	ext{Conc. } HCl$ to reduce the carbonyl group to a methylene group. Matches with $(c)$.$(ii)$. Benzaldehyde $ightarrow$ $1-$Phenylethanol: This is a Grignard reaction where $CH_3MgBr$ attacks the aldehyde,followed by hydrolysis to form a secondary alcohol. Matches with $(d)$.$(iii)$. Cyclohexanone $ightarrow$ Cyclohexanol: This is a reduction of a ketone to a secondary alcohol using $LiAlH_4$. Matches with $(a)$.$(iv)$. Phenyl benzoate $ightarrow$ Benzaldehyde: This is a partial reduction of an ester to an aldehyde using $DIBAL-H$. Matches with $(b)$.Therefore,the correct sequence is $i-c, ii-d, iii-a, iv-b$.

Column-$I$ (Reactions)	Column-$II$ (Reagents)
$(i)$. Benzophenone $\rightarrow$ Diphenylmethane	$(a)$. $LiAlH_4$
$(ii)$. Benzaldehyde $\rightarrow$ $1-$Phenylethanol	$(b)$. $DIBAL-H$
$(iii)$. Cyclohexanone $\rightarrow$ Cyclohexanol	$(c)$. $Zn(Hg) / \text{Conc. } HCl$
$(iv)$. Phenyl benzoate $\rightarrow$ Benzaldehyde	$(d)$. $CH_3MgBr, H_2O$

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