A hydrocarbon with molecular formula C_6H_6 d | vedclass

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(B) The hydrocarbon $C_6H_6$ reacts with $Br_2$ water,indicating the presence of unsaturation (double or triple bonds).Ammoniacal $AgNO_3$ (Tollens' r

Vedclass · Accepted Answer

$1,5-$Hexadiyne

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(B) The hydrocarbon $C_6H_6$ reacts with $Br_2$ water,indicating the presence of unsaturation (double or triple bonds).Ammoniacal $AgNO_3$ (Tollens' reagent) reacts specifically with terminal alkynes $(R-C\equiv CH)$ to form a white precipitate of silver acetylide.$1,3,5-$Cyclohexatriene (Benzene) does not react with $Br_2$ water or ammoniacal $AgNO_3$.$1,5-$Hexadiyne $(HC\equiv C-CH_2-CH_2-C\equiv CH)$ is a terminal alkyne and would give a precipitate,but its formula is $C_6H_6$.However,$1,5-$Hexadiyne is a valid structure for $C_6H_6$ that contains terminal alkyne groups.Given the options,$1,5-$Hexadiyne is the correct structure that satisfies both conditions.

$A$ hydrocarbon with molecular formula $C_6H_6$ decolourises $Br_2$ water and gives a precipitate with ammoniacal $AgNO_3$. The hydrocarbon is:

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