How can the isomeric complexes [Co(NH_3)_6][C | vedclass

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(C) The given complexes are coordination isomers. In $[Co(NH_3)_6][Cr(NO_2)_6]$,the central metal ions are $Co^{3+}$ and $Cr^{3+}$. In $[Cr(NH_3)_6][C

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Electrolysis of their aqueous solutions

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(C) The given complexes are coordination isomers. In $[Co(NH_3)_6][Cr(NO_2)_6]$,the central metal ions are $Co^{3+}$ and $Cr^{3+}$. In $[Cr(NH_3)_6][Co(NO_2)_6]$,the central metal ions are $Cr^{3+}$ and $Co^{3+}$. Both complexes contain the same metal ions in the same oxidation states,so they have the same number of unpaired electrons. However,the metal ions are coordinated to different ligands in the two isomers. By performing electrolysis of their aqueous solutions,the metal ions deposited at the electrodes will be different. In the first complex,$Co$ will be deposited at the cathode from the cationic part,while in the second,$Cr$ will be deposited at the cathode. Thus,electrolysis is the correct method to distinguish them.

How can the isomeric complexes $[Co(NH_3)_6][Cr(NO_2)_6]$ and $[Cr(NH_3)_6][Co(NO_2)_6]$ be distinguished from one another?

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