The species that can have a $trans$-isomer is: ($en = \text{ethane-}1,2\text{-diamine}$,$ox = \text{oxalate}$)

  • A
    $[Pt(en)Cl_2]$
  • B
    $[Pt(en)_2Cl_2]^{2+}$
  • C
    $[Cr(en)_2(ox)]^+$
  • D
    $[Zn(en)Cl_2]$

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Similar Questions

Why do compounds having similar geometry have different magnetic moments?

Match List $I$ with List $II$ :
List $I$ (Complex)List $II$ (Type of isomerism)
$A$. $[Pt(NH_3)_2Cl_2]$$I$. Optical
$B$. $[Co(en)_3]^{3+}$$II$. Solvate
$C$. $[Co(NH_3)_5NO_2]Cl_2$$III$. Geometrical
$D$. $[Cr(H_2O)_6]Cl_3$$IV$. Linkage

Choose the correct answer from the options given below :

What is the correct order of magnetic moment (spin-only value in $B.M.$)? (Atomic numbers: $Mn = 25, Fe = 26, Co = 27$)

The complex(es),which can exhibit the type of isomerism shown by $[Pt(NH_3)_2 Br_2]$,is(are) [en $= H_2 NCH_2 CH_2 NH_2$ ]
$(A)$ $[Pt(en)(SCN)_2]$
$(B)$ $[Zn(NH_3)_2 Cl_2]$
$(C)$ $[Pt(NH_3)_2 Cl_4]$
$(D)$ $[Cr(en)_2(H_2 O)(SO_4)]^{+}$

The complex ion $[Pt(NO_2)(Py)(NH_3)(NH_2OH)]^+$ will give $..........$ geometrical isomers.

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