How much charge in coulombs is required for t | vedclass

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(B) The reduction reaction is: $Al^{3+} + 3e^{-} \longrightarrow Al$. According to the reaction,$1 \ 	ext{mole}$ of $Al^{3+}$ requires $3 \ 	ext{mol

Vedclass · Accepted Answer

$2.895 	imes 10^{5} \ C$

Vedclass · Answer

(B) The reduction reaction is: $Al^{3+} + 3e^{-} \longrightarrow Al$. According to the reaction,$1 \ 	ext{mole}$ of $Al^{3+}$ requires $3 \ 	ext{moles}$ of electrons for reduction to $Al$. We know that $1 \ 	ext{mole}$ of electrons carries a charge of $1 \ F = 96500 \ C$. Therefore,the charge required for $3 \ 	ext{moles}$ of electrons is $3 	imes 96500 \ C = 289500 \ C$. This can be expressed in scientific notation as $2.895 	imes 10^{5} \ C$.

How much charge in coulombs is required for the reduction of one mole of $Al^{3+}$ to $Al$?

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