1 mole of electrons corresponds to how much F | vedclass

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Question

(A) The charge of $1$ mole of electrons is defined as $1$ Faraday $(F)$.
$1 \ F = N_A 	imes e^-$,where $N_A$ is Avogadro's number $(6.022 	imes

Vedclass · Accepted Answer

$1 \ F, 96500 \ C, 6.022 	imes 10^{23} \ 	ext{electrons}$

Vedclass · Answer

(A) The charge of $1$ mole of electrons is defined as $1$ Faraday $(F)$.
$1 \ F = N_A 	imes e^-$,where $N_A$ is Avogadro's number $(6.022 	imes 10^{23} \ 	ext{mol}^{-1})$ and $e^-$ is the charge of a single electron $(1.602 	imes 10^{-19} \ C)$.
Therefore,$1 \ F = 6.022 	imes 10^{23} 	imes 1.602 	imes 10^{-19} \ C \approx 96500 \ C$.
Thus,$1$ mole of electrons equals $1 \ F$,$96500 \ C$,and $6.022 	imes 10^{23}$ electrons.

$1$ mole of electrons corresponds to how much Faraday,how much Coulomb,and how many electrons?

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