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(A) The given number is $7326985$.First,arrange the digits of the number in ascending order: $2, 3, 5, 6, 7, 8, 9$.Now,compare the number of digits be

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Three

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(A) The given number is $7326985$.First,arrange the digits of the number in ascending order: $2, 3, 5, 6, 7, 8, 9$.Now,compare the number of digits between pairs in the original number $(7326985)$ and the rearranged sequence $(2356789)$:$1$. Pair $(7, 3)$: In original,$0$ digits between them. In rearranged,$0$ digits between them ($2, 3, 5, 6, 7, 8, 9$ - $3$ and $7$ have $5, 6$ between them,so this is not a match).Let's check all pairs:Original: $7, 3, 2, 6, 9, 8, 5$Sorted: $2, 3, 5, 6, 7, 8, 9$Pairs in original:$(7, 3): 0$ digits between. In sorted: $3, 5, 6, 7$ ($3$ digits between).$(7, 2): 1$ digit between. In sorted: $2, 3, 5, 6, 7$ ($3$ digits between).$(3, 2): 0$ digits between. In sorted: $2, 3$ ($0$ digits between). Match found: $(3, 2)$.$(6, 9): 0$ digits between. In sorted: $6, 7, 8, 9$ ($2$ digits between).$(6, 8): 1$ digit between. In sorted: $6, 7, 8$ ($1$ digit between). Match found: $(6, 8)$.$(9, 8): 0$ digits between. In sorted: $8, 9$ ($0$ digits between). Match found: $(9, 8)$.$(8, 5): 1$ digit between. In sorted: $5, 6, 7, 8$ ($2$ digits between).The matching pairs are $(3, 2), (6, 8), (9, 8)$.There are $3$ such pairs.

How many such pairs of digits are there in the number $7326985$ each of which has as many digits between them in the given number as when the digits of the number are rearranged in ascending order within the number?

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