How many of the following molecules have two lone pairs of electrons on the central atom?
$SF_6$,$BF_3$,$ClF_3$,$PCl_5$,$BrF_5$,$XeF_4$,$H_2O$,$SF_4$

Which of the following compounds has the smallest bond angle $(X - A - X)$ in each series respectively?
$(A) \ OSF_2 \ \ \ \ \ \ \ \ \ OSCl_2 \ \ \ \ \ \ \ \ \ OSBr_2$
$(B) \ SbCl_3 \ \ \ \ \ \ \ \ \ SbBr_3 \ \ \ \ \ \ \ \ \ SbI_3$
$(C) \ PI_3 \ \ \ \ \ \ \ \ \ \ \ \ AsI_3 \ \ \ \ \ \ \ \ \ \ \ \ SbI_3$

The bond angles in methane $(I)$,ammonia $(II)$,and trimethylamine $(III)$ increase in the order:

Match the following:

List-$I$	List-$II$
$A. BrF_5$	$I. AB_4E$,see-saw
$B. SF_4$	$II. AB_4E_2$,square planar
$C. XeF_4$	$III. AB_5E$,square pyramidal
$D. ClF_3$	$IV. AB_3E_2$,$T$-shape

The correct answer is:

Find the maximum number of atoms present in the same plane in a $PCl_5$ molecule.

The sets of molecules in which the central atom has no lone pair of electrons are:
$i$. $SnCl_2, NH_3, SF_4$
$ii$. $HgCl_2, SO_3, SF_6$
$iii$. $BeCl_2, BF_3, PCl_5$
$iv$. $ClF_3, BrF_5, XeF_6$