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Question

(C) The molecular geometries are determined by $VSEPR$ theory:						Molecule			Type			Shape							$BrF_5$			$AB_5E$			Square pyramidal							$SF_4$

Vedclass · Accepted Answer

$A-III, B-I, C-II, D-IV$

Vedclass · Answer

(C) The molecular geometries are determined by $VSEPR$ theory:						Molecule			Type			Shape							$BrF_5$			$AB_5E$			Square pyramidal							$SF_4$			$AB_4E$			See-saw							$XeF_4$			$AB_4E_2$			Square planar							$ClF_3$			$AB_3E_2$			$T$-shape			Matching the items:$A$ $(BrF_5)$ matches $III$ ($AB_5E$,square pyramidal).$B$ $(SF_4)$ matches $I$ ($AB_4E$,see-saw).$C$ $(XeF_4)$ matches $II$ ($AB_4E_2$,square planar).$D$ $(ClF_3)$ matches $IV$ ($AB_3E_2$,$T$-shape).Therefore,the correct match is $A-III, B-I, C-II, D-IV$.

List-$I$	List-$II$
$A. BrF_5$	$I. AB_4E$,see-saw
$B. SF_4$	$II. AB_4E_2$,square planar
$C. XeF_4$	$III. AB_5E$,square pyramidal
$D. ClF_3$	$IV. AB_3E_2$,$T$-shape

Molecule	Geometry
$(a) SnCl_2$	$(i)$ Angular (or) Bent
$(b) XeF_4$	$(ii)$ See-saw
$(c) ClF_3$	$(iii)$ Square pyramidal
$(d) IF_5$	$(iv)$ $T$-shape
-	$(v)$ Square planar

Match the following:

List-$I$ List-$II$

$A. BrF_5$ $I. AB_4E$,see-saw

$B. SF_4$ $II. AB_4E_2$,square planar

$C. XeF_4$ $III. AB_5E$,square pyramidal

$D. ClF_3$ $IV. AB_3E_2$,$T$-shape

The correct answer is:

Similar Questions

Among $NO_3^{-} (I)$,$AsO_3^{3-} (II)$,$CO_3^{2-} (III)$,$ClO_3^{-} (IV)$,and $SO_3^{2-} (V)$,the non-planar species are:

Match the following?
Molecule Geometry
$(a) SnCl_2$ $(i)$ Angular (or) Bent
$(b) XeF_4$ $(ii)$ See-saw
$(c) ClF_3$ $(iii)$ Square pyramidal
$(d) IF_5$ $(iv)$ $T$-shape
- $(v)$ Square planar

What is the correct order of bond angles in the given molecules?

Which of the following is not correctly matched?

$A$ central atom in a molecule has two lone pairs of electrons and forms three single bonds. The shape of this molecule is

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Match the following: List-$I$ List-$II$ $A. BrF_5$ $I. AB_4E$,see-saw $B. SF_4$ $II. AB_4E_2$,square planar $C. XeF_4$ $III. AB_5E$,square pyramidal $D. ClF_3$ $IV. AB_3E_2$,$T$-shape The correct answer is: