How many neutral points will be obtained when a bar magnet is kept with magnetic moment parallel to earth's magnetic field?

Consider the plane $\mathrm{S}$ formed by the dipole axis and the axis of earth. Let $\mathrm{P}$ be point on the magnetic equator and in $\mathrm{S}$. Let $\mathrm{Q}$ be the point of intersection of the geographical and magnetic equators. Obtain the declination and dip angles at $\mathrm{P}$ and $\mathrm{Q}$

The vertical component of earth's magnetic field is zero at or The earth's magnetic field always has a vertical component except at the

The angle of dip at a place is $40.6°$ and the intensity of the vertical component of the earth's magnetic field $V = 6 \times {10^{ - 5}}$ $Tesla$. The total intensity of the earth's magnetic field $ (I) $ at this place is

Two short bar magnets of magnetic moments $m$ each are arranged at the opposite corners of a square of side $d$ such that their centres coincide with the corners and their axes are parallel. If the like poles are in the same direction, the magnetic induction at any of the other corners of the square is

At the magnetic north pole of the earth, the value of horizontal component of earth's magnetic field and angle of dip are, respectively